Question

28.
Card Game
in school, cards competition was held. Two students Daman and Chaman of class VIII A are
provided the cards. The cards in their hands are of different colours as shown below:
5
4
3
8.
16
7
In order to make sum of the digits of cards in each hand be divisible by 9, what are the minimu
values of x and y?​

Answer 1

Answer:

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Answer 2

Solution :-

we know that,

• if sum of digits of a number is divisible by 9, the given number also divisible by 9 .

so, Daman's cards :-

→ (5 + 4 + x + 6) ÷ 9 = Remainder 0 .

→ (15 + x) ÷ 9 = Remainder 0 .

Possible value of x :-

• when x = 3 => 15 + 3 = 18 = divisible by 9.

similarly, Chaman's cards :-

→ (3 + 8 + y + 7) ÷ 9 = Remainder 0 .

→ (18 + y) ÷ 9 = Remainder 0 .

Possible value of y :-

• when y = 9 => 18 + 9 = 27 = divisible by 9.

therefore, value of x is 3 and value of y is 9.

also,

→ Daman's score = 18 .

→ Chaman's score = 27 .

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