Science, asked by lkumari1194, 5 months ago

28. If Sin (A+2B)=+ and Cos fA+4B)=1/12, AB then find A and B.

Answers

Answered by Anonymous
0

Explanation:

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Answered by rashi200524
6

Explanation:

Given, sin(A+2B)= 23

cos(A+4B)=0

A>B,

We know that, sin60 ∘= 23 and cos90=0

Consider,

sin(A+2B)= 23 and sin60 = 23

​⟹(A+2B)=60 ∘---------------(i)

Consider,

cos(A+4B)=0 and cos90 ∘=0

⟹(A+4B)=90 ∘ ---------------(ii)

Solve (i) and (ii) :

(A+2B)=60∘

(A+4B)=90∘

Subtracting (i) from (ii),

2B=30 ∘

B= 30/2 ∘=15 ∘

From (ii)

(A+4B)=90 ∘

Also, B=15 ∘

A=90 ∘ −60 ∘

A=30 ∘

∴A=30 ∘ ,B=15 ∘

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