28 of nitrogen reeds with 6g of hydrogen completely as per as the given equation to floom ammonia. How much will be the mass of ammonia formed ?
Vaibhavi987:
the equation is - N2 + 3H + 2NH3
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The balanced equation for the reaction is:
3H2 (g) + N2 (g) -> 2NH3 ... 3mol
H2 react with 1 mol N2 to produce 2 mol NH3
Mass of 8 mol NH3 = 8*17 = 136g NH3 produced.
6g of hydrogen will react with 28g of nitrogen to give 34g ofammonia.
the equation is - N2 + 3H + 2NH3
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