Question

28.
The displacement of a particle starting from rest
(at t=0) is given by s = 6t2 – 13
The time when the particle will attain zero velocity
again, is :
(1) 45 (2) 8 (3) 12 (4) 165​

Answer 1

$\huge{\mathcal{\pink{Answer}}}$

first the velocity of the particle

(using differentiation)

$\frac{ds}{dt} = \frac{d(6 t {}^{2} - 13 ) }{dt}$

$\huge{\mathcal{\boxed{\pink{(12t)m/s}}}}$

➡now the time when the particle attain 0 velocity

$\large{(12t)m/s=0}$

$\huge{\mathcal{\boxed{\blue{t=0second}}}}$