Math, asked by navnoorx, 2 months ago

28. Using distance formula, find the area of the rhombus ABCD, if its vertices are A(3,01
B(4, 5), C(-1, 4) and D(-2, -1).​

Answers

Answered by prashantgonge953
0

Answer:

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Step-by-step explanation:

Let the rhombus ABCD and their points are, A(3,0),B(4,5),C(−1,4),D(2,−1) respectively,

Let the diagonals are AC,BD

By distance formula 

AC=42+42=32

BD=22+62=40

Area of the rhombus =21×AC×BD=213240

Therefore,

Area =85 .

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