Chemistry, asked by aparna5409, 4 months ago

280 ml of sulphur vapour at NTP
weigh 3.2 gm. The molecular formula
of the sulphur vapour is​

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Answered by rajsuhagiya
0

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280 ml of sulphur vapour at ntp weigh 3.2 g. the molecular formula of the sulpher vapour is????

Asked by ayushikas | 22nd May, 2011, 10:23: PM

Expert Answer:

As we know density of a gas = Mass/Volume = 3.2gm / 280mL

Molecular mass = Molar volume x density

As molar volume at N.T.P = 22.4L = 22.4 x 1000mL

So molecular mass = 22.4 x 1000 x 3.2 / 280 = 256

Now molecular formula = n x Empirical formula

n = Molecular mass / Empirical formula mass

Empirical formula mass for sulphur is = 32

So, n = 256 / 32 = 8

Hence molecular formulaof sulphur vapour is = 8 x (S)

= S8

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