Question

28g of N2mixed with 28g of H2 and they are made to react with each other then maximum weight of ammonia formed is

Answer 1

Answer:

Explanation:

Limiting reagent in a reaction is the one which is consumed totally before the total consumption of any other reactant and for the calculation of the same, it is better to do the calculations on mole basis.

So, for the given condition first let we calculate the number of moles of each reactant-

As we know,

Number of moles = Weight (in grams)/Molecular Wt.

Mol. Wt. of N2- 28

Mol. Wt. of H2- 2

Since, we have 28g of N2 & 12g of H2

Thus,

No. of moles of N2- 28/28 = 1 mole

& No. of moles of H2- 12/2 = 6 moles

Now, from the stoichiometry of the reaction

N2 + 3H2 → 2NH3