Question

28p^2q^2r-42pq^2r^2
factorise​

Answer 1

Answer:

\sf{r(1 - 2pqr)}

Step-by-step explanation:

Given : \sf{ {\dfrac{3pqr - 6p^2q^2r^2}{3pq}}}

On further solving, we get

→ \sf{ {\dfrac{3pq(r - 2pqr^2)}{3pq}}}

→ \sf{ {\dfrac{ {\cancel{3pq}} (r - 2pqr^2)}{ {\cancel{3pq}} }}}

→ \sf{r - 2pqr^2}

→ r(1 - 2pqr)

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Answer 2

Answer:

14pq²r(2p - 3r)

Step-by-step explanation:

28p^2q^2r-42pq^2r^2 = 14pq²r(2p-3r)