28p^2q^2r-42pq^2r^2
factorise
Answers
Answered by
0
Answer:
\sf{r(1 - 2pqr)}
Step-by-step explanation:
Given : \sf{ {\dfrac{3pqr - 6p^2q^2r^2}{3pq}}}
On further solving, we get
→ \sf{ {\dfrac{3pq(r - 2pqr^2)}{3pq}}}
→ \sf{ {\dfrac{ {\cancel{3pq}} (r - 2pqr^2)}{ {\cancel{3pq}} }}}
→ \sf{r - 2pqr^2}
→ r(1 - 2pqr)
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Answered by
4
Answer:
14pq²r(2p - 3r)
Step-by-step explanation:
28p^2q^2r-42pq^2r^2 = 14pq²r(2p-3r)
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