[29-(-2){6-(7-3)}]÷[3×{5+(-3)×(-2)}]
Answers
[29-(-2){6-4}]÷[3x{5+6}]
[29-(-2)x2] ÷[3x11] = [ 29- (-4)]÷33 = 33÷33 = 1
so here is your ans. , friend , it is 1
[29 - (-2) {6 - (7 - 3)}] ÷ [3 × {5 + (-3) × (-2)}] = 1
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Let's understand a few concepts first:
In order to solve any given simplification problem, we must follow the below-mentioned rules:
V → Vinculum ( or, Bar )
B → Brackets ( remove the brackets in following the order → (), {}, [] )
O → Of
D → Division ( ÷ )
M → Multiplications ( × )
A → Addition ( + )
S → Subtraction ( - )
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Let's now solve the given problem:
[29 - (-2) {6 - (7 - 3)}] ÷ [3 × {5 + (-3) × (-2)}]
- we will solve inside the round brackets
= [29 - (-2) {6 - (4)}] ÷ [3 × {5 + (-3) × (-2)}]
- we will open the round brackets
= [29 + 2 {6 - 4}] ÷ [3 × {5 + 6}]
- we will solve inside the curly brackets
= [29 + 2 {2}] ÷ [3 × {11}]
- we will open the curly brackets
= [29 + 2 × 2] ÷ [3 × 11]
= [29 + 4] ÷ [3 × 11]
- we will solve inside the square brackets
= [33] ÷ [33]
- we will open the square brackets
= 33 ÷ 33
= 1
Thus, [29 - (-2) {6 - (7 - 3)}] ÷ [3 × {5 + (-3) × (-2)}] = 1.
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