Question

29.
A hemispherical tank, of diameter 3m. is full of water. It is being emptied by a pipe at the rate of
2/3 litres per second. How much time will it take to make the tank three-fourth empty? T = 22 |​

Answer 1

Answer:

Step-by-step explanation:

The Formula for finding the volume of a Hemispherical Tank is:

= $\frac{2}{3} \pi r^{3}$

Now,

The Diameter is = 3 m

⇒ Radius = 1.5 m

Here,

To find the volume:

Volume of the tank = $\frac{2}{3} \pi r^{3}$

⇒ 2/3 × π (Take 3.14) × (1.5 m)³

⇒ 2/3 × 3.14 × 2.25 m²

⇒ 2 × 10.5975 m³

⇒ Volume of the Tank = 21.195m³

To convert 'Volume' to 'Liquidate Volume':

1 cm³ = 1 ml

1000 cm³ (or : 1 dm³) = 1 litre

1 m³ = 1000 litre

Here,

Volume of Water = Volume ( in m³) × 1000 litres

Volume of Water in the tank:

= 21.195 m³ × 1000 litres

⇒ Volume of Water present in the Tank = 21,195 litres

So,

Speed of water drainage = 2/3 litre per second

Time Taken to empty the Tank = Volume ÷ Speed

⇒$\frac{21195}{\frac{2}{3} }$ seconds

⇒ (21195 × 3) ÷ 2

⇒ 31,792.5‬ seconds...

Hope you've Got the Answer...