Question

29. An ideal gas expands according to the law
p2V = constant. The internal energy of the gas

Answer 1

Explanation:

An ideal gas expands according to the law P2V = constant. The internal energy of the gas (1) Increases continuously (2) Decreases continuously (3) Remain constant (4) First increases and then decreases

An ideal gas expands according to the law P2V = constant. The internal energy of the gas

(1) Increases continuously

(2) Decreases continuously

(3) Remain constant

(4) First increases and then decreases

Answer 2

The internal energy of the gas increases.

Explanation:

Given,

            ⇒ $P^{2}V$ = constant

We know that the work done,

            ⇒ w =  $\int^{v2} _{v1} (PdV)$

             ⇒ $P^{2}V$ = a

            ⇒ $P^{2}$= $\frac{a}{v}$

         ⇒  P = $\sqrt{\frac{a}{v} }$

         ⇒ W = $\int^{v2} _{v1} (V^{\frac{-1}{2} } dV)$

       ⇒ W = 2 x $\sqrt{a}$ $\int^{v2} _{v1} (V_{2} ^{\frac{1}{2}} -V_{1} ^{\frac{1}{2} }) dV$

here, the volume $V_{2}$ is greater than the volume $V_{1}$ for the work done be positive.

So, there must be the increase in internal energy.

Internal energy is the energy that a system inside it. It is not a path function and it is not a property.