29. Factorize : 2x+4y2+822–2V2xy+4V2yz-8xz
Answers
Answered by
1
Answer:
Given : 2x+4y−8xy−1
We can further write it as
2x+4y−8xy−1=2x−1−8xy+4y
By taking common terms out
2x+4y−8xy−1=(2x−1)−4y(2x−1)
So we get,
2x+4y−8xy−1=(2x−1)(1−4y)
Answered by
0
Answer:
Given : 2x+4y−8xy−1
We can further write it as
2x+4y−8xy−1=2x−1−8xy+4y
By taking common terms out
2x+4y−8xy−1=(2x−1)−4y(2x−1)
So we get,
2x+4y−8xy−1=(2x−1)(1−4y)
Step-by-step explanation:
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