Question

29. Factorize : 2x+4y2+822–2V2xy+4V2yz-8xz​

Answer 1

Answer:

Given : 2x+4y−8xy−1

We can further write it as

2x+4y−8xy−1=2x−1−8xy+4y

By taking common terms out

2x+4y−8xy−1=(2x−1)−4y(2x−1)

So we get,

2x+4y−8xy−1=(2x−1)(1−4y)

Answer 2

Answer:

Given : 2x+4y−8xy−1

We can further write it as

2x+4y−8xy−1=2x−1−8xy+4y

By taking common terms out

2x+4y−8xy−1=(2x−1)−4y(2x−1)

So we get,

2x+4y−8xy−1=(2x−1)(1−4y)

Step-by-step explanation: