Question

29. If sin(x-20) =cos(3x-10) then find the value of x.​

Answer 1

★ Question :

If sin (x - 20) =  cos (3x - 10) , then find the value of x .

★ Solution :

sin (x - 20) = cos (3x - 10)

We know that ,

• sin (90 - θ) = cos θ

➠ sin (x - 20) = sin (90 - (3x - 10))

➠ sin (x - 20) = sin (90 - 3x + 10)

➠ sin (x - 20) = sin (100 - 3x)

By applying sin⁻¹ on both sides ,

➠ sin⁻¹[sin (x - 20)] = sin⁻¹[sin(100 - 3x)]

We know that ,

• sin⁻¹(sin x) = x

➠ (x - 20) = (100 - 3x)

➠ x + 3x = 100 + 20

➠ 4x = 120

➠ x = 30 $\pink{\bigstar}$

Value of x = 30° .

Answer 2

Answer:

X=30°

Step-by-step explanation:

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