Question

29. If the roots of the Quadratic equation (a-b)x²+(b-c) x + (c-a) =0 are equal. Then
prove
that 2a = btc.​

Answer 1

Answer:

2a=b+c

Step-by-step explanation:

(b-c)²-4(a-b) (c-a)=0

(b-c)²=4(a-b) (c-a)

b²+c²-2bc=4(ac-a²-bc+ab)

b²+c²-2bc=4ac-4a²-4bc+4ab

4a²+b²+c²+2bc-4ab-4ac=0

[2a-(b+c)²]=0

2a=b+c