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Prove that the parallelograms on equal (or same) bases and between the same parallels
are equal in area
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Answer:
Suppose AL and PM are the altitudes corresponding to equal bases AB and PQ of ||gm ABCD and PQRS respectively .
Since the ||gm are between the same parallels PB and SC.
∴ AL = PM
Now, ar(||gm ABCD) = AB × AL
ar(||gm PQRS) = PQ × PM
But, AB = PQ [given]
AL = PM [proved]
∴ ar(||gm ABCD) = ar(||gm PQRS)
Step-by-step explanation:
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