Question

29 sulekha ate 3/8 of the chocolates she had on a day and 4/5of the remainder on the second day. If the number of chocolates left in the box is 40, how many chocolates the box had initially

Answer 1

Answer:

Ist day. ate3/8 chocolate

Balance = 5/8

2nd day=5/8x4/5= 1/2

Total chocolate she ate = 3/8+1/2

6+8/16=14/16=7/8

Balance =I-7/8=1/8

Let there be total x chocolate

then Xx1/8=40

x =320

Total chocolate is 320

Answer 2

There are 80 chocolates the box had initially.

Step-by-step explanation:

Since we have given that

Part of chocolates she had on a day = $\dfrac{3}{8}$

Remaining part of chocolates would be

$1-\dfrac{3}{8}\\\\=\dfrac{8-3}{8}\\\\=\dfrac{5}{8}$

Part of chocolates on second day would be

$\dfrac{4}{5}\times \dfrac{5}{8}\\\\=\dfrac{4}{8}\\\\=\dfrac{1}{2}$

So, Remaining part of chocolates now = $1-\dfrac{1}{2}=\dfrac{1}{2}$

Let the number of chocolates be 'x'.

According to question, it becomes,

$\dfrac{1}{2}\times x=40\\\\x=40\times 2\\\\x=80$

Hence, there are 80 chocolates the box had initially.

# learn more:

15 1/2 kg chocolates is put in 3/4 kg boxes .find the number if boxes if each box is filled with 3/4 kg of chocolates. how many chocolates are left

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