Question

29. Suppose that a hypothetical atom gives a
red, green, blue and violet line spectrum.
Which jump according to figure would give
off the red spectral line.
n=4 -
n = 3
n = 2
n = 1
1) 3 + 1
2) 2 →
3) 4 - 1
4) 3 2​

Answer 1

Given:

A hypothetical atom gives a red, green, blue and violet line spectrum.

To find:

Transition of electrons that would give red spectral line.

Solution:

As per Rydberg's Formula , the wavelength of the electromagnetic waves generated due to transition of electrons (in Hydrogen) is given as:

$\boxed{ \sf{ \lambda = R \: \bigg \{ \dfrac{1}{ {(n1)}^{2} } - \dfrac{1}{ {(n2)}^{2} } \bigg \}}}$

As per this Equation , lower the difference between the orbits of atom , higher will be the wavelength of Electromagnetic wave.

So , n1 and n2 should be close so as to emit red light (high wavelength).

So, transition from n=3 $\rightarrow$ n=2 will emit red light.

So, final answer is:

$\boxed{ \bold{ 3 \: \longrightarrow \: 2}}$

Answer 2

Explanation:

Given:

A hypothetical atom gives a red, green, blue and violet line spectrum.

To find:

Transition of electrons that would give red spectral line.

Solution:

As per Rydberg's Formula , the wavelength of the electromagnetic waves generated due to transition of electrons (in Hydrogen) is given as:

\boxed{ \sf{ \lambda = R \: \bigg \{ \dfrac{1}{ {(n1)}^{2} } - \dfrac{1}{ {(n2)}^{2} } \bigg \}}}

λ=R{

(n1)

2

1

−

(n2)

2

1

}

As per this Equation , lower the difference between the orbits of atom , higher will be the wavelength of Electromagnetic wave.

So , n1 and n2 should be close so as to emit red light (high wavelength).

So, transition from n=3 \rightarrow→ n=2 will emit red light.

So, final answer is:

\boxed{ \bold{ 3 \: \longrightarrow \: 2}}

3⟶2