Question

29. The adjacent sides of a parallelogram are 32 cm and 24 cm. If the distance between the longer sides is 17.4 cm, find the distance between the shorter sides.



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Answer 1

Step-by-step explanation:

Longer side = 32 cm

Shorter side = 24 cm

Let the distance between the shorter sides be x cm.

Area of a parallelogram = Longer side x Distance between the longer sides = Shorter side x Distance between the shorter sides

Height of the parallelogram is twice the base

Height = 2b m

Area of a parallelogram = Base x Height

Answer 2

➡Longer side = 32 cm

➡ Shorter side = 24 cm

➡ Let the distance between the shorter sides be x cm.

Area of a parallelogram = Longer side x

Distance between the longer sides

➡ Shorter side x Distance between the shorter

Or, 32x17. 4 = 24×x

Or,

$x \times \frac{32 \times 17.4}{24 } = 23.2cm$

Height of the parallelogram is twice the base Height

= 2b m Area of a parallelogram = Base xHeight

$392 = b \times 2b \\ 392 = 2 {b}^{2} \\ \frac{392}{2} = {b}^{2} \\ 196 = {b}^{2} \\ b = 14 \\ therefore.base = 14m \\ altitude = 2 \times base = 2 \times 14 = 28m$

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