Math, asked by hemalathak939, 18 days ago

the age of mohan is 5 years more than that of his brother. 5 years ago, the ratio of their ages is 3:2. find their present ages​

Answers

Answered by subhadip3199
1

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Answered by Anonymous
2

Given,

The age of mohan is 5 years more than that of his brother.

5 years ago, the ratio of their ages is 3:2

To find,

Their present age.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Let, the present age of Mohan's brother = x years

Present age of Mohan = x+5 years

Five years ago,

Age of Mohan's brother = x-5 years

Age of Mohan = x+5-5 = x years

According to the data mentioned in the question,

x/x-5 = 3/2

2x = 3x-15

3x-2x = 15

x = 15

Present age of Mohan's brother = 15 years

Present age of Mohan = 15+5 = 20 years

Hence, present age of Mohan's brother is 15 years and present age of Mohan is 20 years.

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