Chemistry, asked by student8374, 10 months ago

29. The mass % of NaOH in 5 molal aqueous NaOH
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Answered by ag3192692
4

Answer:

16.66%

  • Explanation Let mole of solvent be 1 kg Molality =mole of solute /Mass of solvent
  • By this formula we get mole of NAOH =5
  • MASS OF NAOH =5×40=200
  • Total mass of solution = massof solute + mass of solvent =1000+200=1200g

%mass=200×100/1200=16.66%

Answered by unique1646
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