29. The mass % of NaOH in 5 molal aqueous NaOH
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16.66%
- Explanation Let mole of solvent be 1 kg Molality =mole of solute /Mass of solvent
- By this formula we get mole of NAOH =5
- MASS OF NAOH =5×40=200
- Total mass of solution = massof solute + mass of solvent =1000+200=1200g
%mass=200×100/1200=16.66%
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