Question

29. Two riffles fire the same number of bullets in
a given interval of time. The second fires
bullets of mass twice that fired by the first
and with a velocity that is half that of the first.
The ratio of their powers is
1) 1:4 2) 4:13) 1:24) 2:1
please send answer with full explanation​

Answer 1

Answer:

Power of First Bullet : Power of second bullet :: 2 : 1

Explanation:

Power   = Energy / Time

Energy = (1/2)mV²

Power of First Bullet  =  (1/2) M V² / T

second bullet  Mass = 2M  & Velocity = V/2

Power of second bullet = (1/2) (2M)  (V/2)² / T

= (1/2) M V² / 2T

Power of First Bullet / Power of second bullet   =  ( (1/2) M V² / T ) / ((1/2) M V² / 2T)

= 2

Power of First Bullet : Power of second bullet :: 2 : 1