Question

(2a+1/2b+3c)²


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Answer 1

Answer:

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Step-by-step explanation:

ANSWER

The given expression (4a−2b−3c)2 can be solved as shown below:

(4a−2b−3c)2

=(4a)2+(−2b)2+(−3c)2+(2×4a×(−2b))+(2×(−2b)×(−3c))+(2×(−3c)×4a)

(∵(a+b+c)2=a2+b2+c2+2ab+2bc+2ca)

=16a2+4b2+9c2−16ab+12bc−24ca

Hence, (4a−2b−3c)2=16a2+4b2+9c2−16ab+12bc−24ca.

Answer 2

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