Question

2A (2 MOLE)+ B (1 MOLE) = AB (2 MOLE) given amount a=16 mole and b= 22mole find ab​

Answer 1

Answer:

(i) 200 molecules of B will react with 200 atoms of A and 100 atoms of A will remain unreacted. Hence, B

2

is the limiting reagent.

(ii) 2 moles of A will react with 2 moles of B

2

and 1 mole of B

2

will remain unreacted. Thus, A is the limiting reagent.

(iii) 100 atoms of A will react with 100 molecules of B

2

. Thus, both reagents are present in stoichiometric amounts.

(iv) 2.5 mole of B

2

will react with 2.5 mole of A and 2.5 mole of A will remain unreacted. Hence, B

2

is the limiting reagent.

(v) 2.5 moles of A will react with 2.5 moles of B

2

and 2.5 moles of B

2

will remain unreacted. Thus, B

2

is the limiting reagent.