Question

2a^3+16b^3-3a-6b factorise this

Answer 1

HEY !!! HERE IS YOUR ANSWER 》》

2a3 +16b3–3a–6b

= 2(a3+ 8b3)–3(a+2b)

=2 (a+2b) (a2+ 4b2–2ab) –3(a+2b)

=(a+2b)(2a2 +8b2–4ab–3)

HOPE IT HELPS ^_^

Answer 2

Answer:

Step-by-step explanation:

2[a^3+8b^3]-3[a+2b].         Remove the common terms

[a+b][a^2-ab+b^2]               Use the formula for addition of cubes

2[a^3+2b^3]-3[a+2b].          2b^3 as in for 8s cube

[a+2b][(a^2-2ab+(2b)^2]

[a+2b][2(a^2-2ab+2b^2-3]  We take 2 and -3 because they are part of term.    

Hope you understood........