Math, asked by noyonikabhattacharyy, 9 months ago

(2a+3b)^2+(2a-3b)^2=8a^2+18b^2

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Answered by kkgurjar350

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Answered by aadityabsingh81

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Question- (2a+3b)^2+(2a-3b)^2=8a^2+18b^2

Answer- 2a^2 + 3b^2 + 2a^2 - 3b^2 = 8a^2 + 18b^2

2a^2 + 2a^2 + 3b^2 - 3b^2 = 8a^2 + 18b^2

4a^2 = 8a^2 + 18b^2

-4a^2 = 18b^2

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