Question

(2a-3b)2+(2a+3b)2 solve using suitable algebraic identity​

Answer 1

Answer:

16a²

Step-by-step explanation:

Let

• 2a + 3b = x

• 2a - 3b = y

According to Question

We have to simplify:

{(2a + 3b)}^{2} + 2(2a + 3b)(2a - 3b) + {(2a - 3b)}^{2}(2a+3b)2+2(2a+3b)(2a−3b)+(2a−3b)2

Therefore, we get

=

${x}^{2} + 2xy + {y}^{2}=x2+2xy+y2$

But, this equals to,

=

${(x + y)}^{2}=(x+y)2$

Put the respective values,

$\begin{gathered} = {(2a + 3b + 2a - 3b)}^{2} \\ \\ = {(4a)}^{2} \\ \\ = \sf{ 16 {a}^{2} }\end{gathered}=(2a+3b+2a−3b)2=(4a)2=16a2$

Answer 2

Step-by-step explanation:

refer the attachment hope it's helpful to you