Math, asked by gaddamsrivallireddy, 1 year ago

(2a+3b)(2c-3d) =(2a-3b) (2c+3d)


vidya6440p41gjd: answer is - left side=(4ac+6ad) (6bc-9bd) right side=(4ac-6ad) (-6bc-9bd)

Answers

Answered by sadikalisait
16

Answer:


Step-by-step explanation:

The way that you do it is:

multiply the left side of the equation:

(2a+3b)( 2c-3d)= 4ac+6bc-6ad-9bd

repeat for the right side:

(2a-3b) (2c+3d)=4ac-6bc+6ad-9bd


4ac+6bc-6ad-9bd = 4ac-6bc+6ad-9bd

move everything to the left side of the equation:

12bc-12ad=0

divide by 12 and move terms over

ad=bc

divide each side by bd

ad/bd=bc/bd

a/b=c/d

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