Question

2a - 3b - [3a - 2b - {a-c-(a - 2b)}]
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Answer 1

$\large\boxed{\sf\green{Solution~:-}}$

$: \implies\sf\red {2a - 3b - [3a - 2b - {(a-c-(a - 2b))}}]$

• Firstly, take terms outside the brackets.

$\boxed{\sf\green{Note~:-~While~removing~the~brackets~the~signs~will~also~be~changed}}$

$: \implies\bold{2a - 3b - [3a - 2b - {(a-c-a + 2b)}}]$

$: \implies\bold{2a - 3b - [3a - 2b - {a + c + a - 2b}}]$

$: \implies\bold{2a - 3b - 3a + 2b + a + c + a - 2b}$

• Now add the like terms.

$: \implies\bold{2a - 3a - 3b+ 2b - 2b+ a + a + c}$

$: \implies\bold{ - a - 3b+ 2a+ c}$

Answer ➣

$\large\boxed{\sf\blue{3b + 2a - a + c}}$

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Know more :-

Signs are changed on the following bases :-

• $\bold{(-)~(-)~=~+}$
• $\bold{(+)~(+)~=~+}$
• $\bold{(+)~(-)~=~-}$
• $\bold{(-)~(+)~=~-}$

[ Refer to the attached image too ]