Math, asked by 8853, 10 months ago

(2a-3b+4c)^2+(2a+3b-4c)^2+2(2a-3b+4c)(2a+3b-4c)

Answers

Answered by bshibani1980
15

Answer:

if you look at the question it is making a formula of (a+b)^2

Step-by-step explanation:

so it will be

(2a-3b+4c+2a+3b-4c)^2

so by eliminating

(2a+2a)^2

(4a)^2

the final answer is

16a^2

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