Question

(2a+3b) (a-2)=2a^2-3b^2

Answer 1

Answer:

Step-by-step explanation:

Do you need to prove whether the equation is true? If so, check this out:

(a+b)(2a-3b)=2a2-ab-3b2  

Equation is alway true

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "b2"   was replaced by   "b^2".  1 more similar replacement(s).

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :  

          (a+b)*(2*a-3*b)-(2*a^2-a*b-3*b^2)=0  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((a+b)•(2a-3b))-(((2•(a2))-ab)-3b2)  = 0  

Step  2  :

Equation at the end of step  2  :

 ((a + b) • (2a - 3b)) -  ((2a2 -  ab) -  3b2)  = 0  

Step  3  :

Equation at the end of step  3  :

 (a + b) • (2a - 3b) -  (2a2 - ab - 3b2)  = 0  

Step  4  :

Equation at the end of step  4  :

 0  = 0  

Step  5  :

Equations which are always true :

5.1    Solve   0  = 0.This equation is a tautology (Something which is always true)

Equation is always true.

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