Math, asked by himaharold, 21 days ago

2a+3b-c, when a=3, b=4 and c=5​

Answers

Answered by prachibarapatre
0

Here we are given an expression 2a+3b-c

Also, the values of a, b, and c are given

a=3, b=4 and c=5​

We have to find the values of the expression

We will put the values of a, b, and c in the given expression

2a+3b-c = 2 ( 3 ) + 3 ( 4 ) - 5

              =  6 + 12 - 5

             = 6 + 7

            = 13

Hence, the value of 2a+3b-c will be 13

Answered by masura8080
0
  • As per the data given in the question, we have to find the value of the expression.

       Given data:- a=3,b=4,c=5.

       To find:- Value of given expression 2a+3b-c.

       Solution:-

  • To solve the above equation we will follow the BODMAS rule.
  • It is the rule used to remember the order of operations to be followed while solving expressions in mathematics.

       where,

         B= bracket

         O= order of power or rules

         D= division

         M= multiplication

         A= addition

         S= subtraction

       Now put the value of a,b, and c in the given equation we get,

        2a+3b-c\\=2(3)+3(4)-5\\=6+12-5\\=18-5\\=13.

      Hence we will get the value 13.

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