Math, asked by Anonymous, 10 months ago

(2a-b)² + 2 (2a-b)-8 = .............?

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Answered by Anonymous

Answer:

$\textbf{Solution:}$

$({2a - b})^{2} + 2(2a - b) - 80$

$= ({2a -b})^{2} + 4(2a - b) - 2(2a - b) - 8$

$= (2a - b){(2a - b) + 4} - 2{(2a - b) + 4}$

$= (2a - b + 4)(2a - b - 2)$

Hope it will be helpful :)....✍️

Answered by Anonymous

$\huge\star\underline\mathtt\purple{Answer:-}$ $<body bgcolor = lavender><marquee direction = "up"><font color = blue>$

${(2a - b)}^{2} + 2(2a - b) - 80$

${(2a - b)}^{2} + 4(2a - b) - 2(2a - b) - 8$

$(2a - b)(2a - b) + 4 - 2(2a - b) + 4$

$(2a - b + 4)(2a - b - 2)$

$<marquee>❤Thanks❤</marquee>$

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