(2a-b)^2+(b-2c)^2=0 (a+c):b=?
Answers
Answered by
2
Answer:
Mark as brainliest answer.
Step-by-step explanation:
→ (2a-b)² + (b-2c)² = 0
→ (2a)² + (-b)² - 2(2a)(-b) + (b)² + (-2c)² + 2(b)(-2c) = 0
→ 4a² + b² + 4ab + b² + 4c² + 4ab - 4bc = 0
→ 4a² + b² + b² + 4c² + 4ab - 4bc = 0
→ 4a² + 2b² + 4c² + 4ab - 4bc = 0
Similar questions