2a-b=9;a+ b=3 this simultaneous equation of 10th std
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2a-b=9--------------(i)
a+b=3--------------(ii)
(THEN, POSITIVE AND NEGATIVE "b" will be cancelled)
We get,
3a=12
a=4
Putting a in eq.2
a+b=3
4+b=3
b=3-4
b=-1
VALUE OF a=4
AND b=-1
a+b=3--------------(ii)
(THEN, POSITIVE AND NEGATIVE "b" will be cancelled)
We get,
3a=12
a=4
Putting a in eq.2
a+b=3
4+b=3
b=3-4
b=-1
VALUE OF a=4
AND b=-1
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