Question

(2a-b-c)^3+(2a-c-a)^3+ (2c-a-b)^3​

Answer 1

(2a-b-c)³+(2a-c-a)³+(2c-a-b)³

(2a+2a+1a+1a)³+(-1b-1b)³(-1c-1c-2c)³

(5+2a)³+(2b)³(2c-2c)³

(6a)³+(2b)³(c)³

Answer 2

Answer:

3(2a-b-c)(2b-c-a)(2c-a-b)

Step-by-step explanation:

We know that, if x+y+z=0; then x3+y3+z3=3xyz

(2a-b-c)+(2b-c-a)+(2c-a-b)=0

∴ (2a-b-c)3+(2b-c-a)3+(2c-a-b)3= 3(2a-b-c)(2b-c-a)(2c-a-b)

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