(2a+b+c) (4a^2+b^2+c^^2-2ab-bc-2ca)
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Answer: 8a^3 + b^3 + c^3 + 2ac^2 - 4abc - 2ac
=> 2a (4a^2 + b^2 + c^2 - 2ab - bc - 2ca) + b (4a^2 + b^2 + c^2 - 2ab - bc - 2ca) + c (4a^2 + b^2 + c^2 - 2ab - bc - 2ca)
=> 8a^3 + 2ab^2 + 2ac^2 - 4a^2b - 2abc - 4ca^2 + 4a^2b + b^3 + bc^2 - 2ab^2 - b^2c - 2ab + 4a^2c - b^2c + c^3 - 2abc - bc^2 - 2ac
=> 8a^3 + 2ac^2 - 4abc + b^3 + c^3 - 2ac
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