(2a-b+c)+(a+b-2c)+(a+2b-c)
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2a-b+c+a+b-2c+a+2b-c,
4a+2b-2c
4a+2b-2c
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0
(2a-b+c)+(a+b-2c)+(a+2b-c)
=2a-b+c+a+b-2c+a+2b-c
=2a+a+a-b+b+2b+c-2c-c
=(2+1+1)a+(-1+1+2)b+(1-2-1)c
=4a+2b-2c
=2(2a+b-c)
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