Question

2a²+3b²+4c² if a= 1 b= -1 c=0​

Answer 1

Answer:

a²+3b²/2a²-3b² = 125/71

Step-by-step explanation:

If a/b=7/3 then find the value of

2a²+3b²/2a²-3b²

a/b=7/3

let say a = 7k  then b = 3k

2a²+3b² = 2 (7k)² + 3(3k)² = 98k² + 27k² = 125k²

2a²-3b² = 2 (7k)² - 3(3k)² = 98k² - 27k² = 71k²

2a²+3b²/2a²-3b² = 125k²/71k²

=>2a²+3b²/2a²-3b² = 125/71

Answer 2

Answer:

$2 {a}^{2} + 3 {b}^{2} + 4 {c}^{2} \\ 2 ({1})^{2} + 3( { - 1})^{2} + 4( {0})^{2} \\ 2 \times 1 + 3 \times 1 + 4 \times 0 \\ 2 + 3 + 0 = 5$

hope it will help you