Math, asked by manojmonika, 11 months ago

2a²+bc-2ab-ac factorise​

Answers

Answered by AccioNerd
42

Answer:

2a² + bc - 2ab - ac = (2a - c)(a - b)

Step-by-step explanation:

2a² + bc - 2ab - ac

= 2a² - 2ab + bc - ac

= 2a(a - b) + c(b - a)

Now switch the signs of the second term

= 2a(a - b) - c(-b + a)

= 2a(a - b) - c(a - b)

= (2a - c)(a - b)

Hope this helps! :)


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Answered by Anonymous
9

Step-by-step explanation:

here your answer :-----------

2a^2+bc-2ab-ac=2a(a-b)-c(a-b)

=(2a-c)(a-b)

i hope its help's u.

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