Math, asked by savage3009, 4 months ago

2ab2c-2a + 3b3c-3b-4b2c2 + 40

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Answered by Anonymous

1

Answer:

ab2c – 2a + 3b3c – 3b – 4b2c2 + 4c. = 2a (b2c – 1) + 3b (b2c – 1) – 4c (b2c – 1). = (b2c – 1) (2a + 3b – 4c) ...

Answered by hitendaksha

0

This is your answer I hope it helps you

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