Science, asked by kavithachilukuri120, 5 months ago

2Agcl(s) gives that Ag(s) +Cl2(g) calculate the number of moles of chlorine gas liberated

Answers

Answered by prafullapradhan6392

22

Answer:

2cln- (1) , cl2(g) +2en thus, the liberation of one more (22.4l) of chlorine

Answered by vengalavishwa

3

Answer:

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Explanation:

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