Question

2as=Vf²-Vi² prove that its dimentionally correct

Answer 1

Answer:

2as = V^2 -Vu^2

so by the principle of homogeneity

# 2as= Vf^2

as 2 is integer so not take in equation

# [LT^-2 ] [L] = [LT^-1 ] ^2

# [L^2 T^-2 ] = [L^2 T^-2 ]

2nd when velocity in initial

same by principle of homogeneity

2as =Vu^2

so as same

# [LT^-2] [L] = [LT^-1 ] ^2

#. [L^2 T^-2 ] = [ L^2 T^-2 ]

hence preove l.hs. = r.h.s