Question

2axy^2+10x+3ay^2+15 factorise

Answer 1

(2axy2+10x)+(3ay2+15)
2x(ay2+5)+3(ay2+5)
(2x+3)(ay2+5)

Answer 2

Given,

2axy² + 10x + 3ay² + 15 is given.

To find,

We have to find the factors of the given 2axy² + 10x + 3ay² + 15.

Solution,

The factors of the 2axy² + 10x + 3ay² + 15 are (ay² + 5) (2x + 3).

We can simply find the factors of 2axy² + 10x + 3ay² + 15 by taking common terms out,

               =2axy² + 10x + 3ay² + 15

               = 2x(ay² + 5) + 3(ay² + 5)

               = (ay² + 5) (2x + 3)

Hence, the factors of the 2axy² + 10x + 3ay² + 15 are (ay² + 5) (2x + 3).