Question

2balls arre dropped from different heights at different instants.second ball is dropped 2seconds after the first ball.of both reach the ground simultaneously after5s of dropping the first ball, then the difference of initial heights of the 2balls will be (g=9.8m/s2)

Answer 1

height of 2nd ball= 1/2 gt2

=1/2 x 9.8 x 3 x 3 = 44.1 (3 taken the ball falls after 2 sec hence 5-2= 3)

height of 1st ball= 1/2gt2

= 1/2 x 9.8 x 5 x 5 = 122.5

1st ball-- 2nd ball = 122.5--44.1= 78.4