Question

2bsquare+ 32b + 128

Factorise using spilting method

Answer 1

Answer:

2b²+32b+128

2b²+16b+16b+128

(2b²+16b)+(16b+128)

2b(b+8)+16(b+8)

(2b+16)(b+8)

2(b+8)(b+8)

Step-by-step explanation:

Answer 2

solutions:

${2b}^{2} + 32b + 128 = 0$

${2b}^{2} + 16b + 16b + 128 = 0$

$2b(b + 8) + 16(b + 8) = 0$

(b+8)(2b+16)=0

b+8=0 or (2b+16)=0

b=-8 or 2b=-16

b=-8 or b=-8