Question

2C2H2 + 5O2 ------》4CO2 +2H2O

100 cm3 of acetylene is mixed with 300 cm3 of pure oxygen and ignited when the reaction takes place as illustrated above. Calculate the excess of oxygen and composition of resulting mixture.​

Answer 1

The above problem involves the use of Gay Lussacs Laws .

The Gay Lussacs Law states that " When gases react , they do so in volumes and bears a simple whole number ratio provided that the physical conditions are constant ."

2 C₂H₂ + 5 O₂ ======> 4 CO₂ + 2 H₂O

100 cm³ of acetylene is mixed with 300 cm³ of pure oxygen and ignited ,

In the above reaction :

Acetylene is C₂H₂ .

O₂ is oxygen .

CO₂ is carbon dioxide .

H₂O is water .

According to the equation :

2 volumes of C₂H₂ + 5 volumes of O₂ ===> 4 volumes of CO₂ + 2 volumes of H₂O

Now it is given that C₂H₅ has 100 cm³ volume .

So 2 volumes = 100 cm³ .

⇒ 1 volume = 100 cm³/2

⇒ 1 volume = 50 cm³

300 cm³ is ignited .

Given 5 volumes of oxygen react .

⇒ 5 × 50 cm³ react .

⇒ 250 cm³ react .

Excess oxygen can be calculated by subtracting the amount of reacted oxygen by total volume of oxygen ignited .

Unused Oxygen = 300 cm³ - 250 cm³

⇒ Unused oxygen = 50 cm³ .

Total volume of the resulting mixture :

4 volumes of CO₂ + 2 volumes of  H₂O

⇒ 4 × 50 cm³ + 2 × 50 cm³

⇒ 200 cm³ + 100 cm³

⇒ 300 cm³

The volume of the resultant mixture is 300 cm³ .

Answer 2

ANSWER:-----------------

{C₂H₂ .}

{O₂ is oxygen .}

{CO₂ is carbon dioxide .}

{H₂O is water .}

equation :

{2 volumes of C₂H₂ + 5 }

{volumes of O₂}

4 volumes of CO₂ + 2

volumes of H₂O

given C₂H₅ has 100 cm³ volume .

So that ,, 2 volumes = 100 cm³ .

⇒

1 volume = 100 cm³/2

⇒

1 volume = 50 cm³

300 cm³ is ignited .

Given 5 volumes of oxygen react .

⇒

5 × 50 cm³ react .

⇒

250 cm³ react .

{oxygen can be calculated}

{total volume of oxygen ignited .}

{Unused Oxygen = 300 cm³ - 250 cm³}

⇒

Unused oxygen = 50 cm³ .

Total volume of the resulting mixture :

4 volumes of CO₂ + 2 volumes of  H₂O

⇒

4 × 50 cm³ + 2 × 50 cm³

⇒

200 cm³ + 100 cm³

⇒ []

{300 cm³}

hence the volume of the resultant mixture is 300 cm³ .

hope it helps:--

T!—!ANKS!!!