2c4H10+13O2. 8Co2+10H2O. 1 mole burns how many attempts of butern and oxigen atom are required
Answers
Answered by
0
Answer:
hope it's helpful
Explanation:
You have your balanced equation
2mol C4H10 + 13mol O2 yields 8mol CO2 + 10mol H2O.
You are interested only in C4H10 and CO2 delete the rest
2 mol C4H10 yields 8 mol CO2
Step 1 : divide by 2
1 mol C4H10 yields 4 mol CO2
Step 2: Multiply through by 3
3 mol C4H10 produces 12 mol CO2
And there is your answer.
Similar questions