√2can be written as p/q so √2 is a rational numbers
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Lets assume √2 is rational.
hence, √2 = p/q where p and q are coprime.
hence, 2q^2 = p^2
hence, p^2 is divisible by 2, and so is p.
therefore, let p = 2r (since p is even)
hence, 2q^2 = 4r^2
or, q^2 = 2r2
hence, even q is even.
let q = 2t
hence, √2 = 2r/2t
and there is a contradiction since p and q cannot have common factors.
Hence, √2 HAS to be irrational.
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