2cos 10+ sin100 +sin1000 + sin 10000 simplifies to ???
A) cos10
B) 3cos10
C) 4cos10
D) 5cos10
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Answer:
5cos10
Explanation:
2cos10 +sin100 +sin1000 +sin10000
By using trigeometric property
sin( 2nπ +θ)=cosθ [there n=odd]
we get
= 2cos10 +sin(90+10 )+sin(90×11+10 )+sin(90×111+10 )
= 2cos10 +cos10 +cos10 +cos10
= 5cos10
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