Question

2cos^2 theta - 3cos theta + 1 = 0​

Answer 1

Answer:

2cos

2

θ+3cosθ=2

Letcosθ=x

2x

2

+3x=2

2x

2

+3x−2=0

2x

2

+4x−x−2=0

2x(x+2)−1(x+2)=0

(x+2)(2x−1)=0

x=−2,

2

1

Sincecosθ



=−2

so,cosθ=

2

1

Answer 2

Answer:

Answer ➹

Question - 2cos^2 theta - 3cos theta + 1 = 0